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5x^2-3x+5=+2x^2+2x-3
We move all terms to the left:
5x^2-3x+5-(+2x^2+2x-3)=0
We get rid of parentheses
5x^2-2x^2-2x-3x+3+5=0
We add all the numbers together, and all the variables
3x^2-5x+8=0
a = 3; b = -5; c = +8;
Δ = b2-4ac
Δ = -52-4·3·8
Δ = -71
Delta is less than zero, so there is no solution for the equation
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